X Olympiad in Informatics 2002/2003

Problem: Sequences without Stammers
Author: Krzysztof Sikora

We consider sequences of letters. We say a sequence x1x2...xn contains a stammer, if we can find in it two occurrences of the same subsequence, one directly following the other, i.e. if for some i and j (1 <= i < j <= (n+i+1)/2) we have xi = xj, xi+1 = xj+1, ..., xj-1 = x2j-i-1.

We are interested in n-element sequences having no stammers, built of the minimal number of different letters.


For n = 3 it is enough to use two letters, say a and b. We have exactly two 3-element sequences without stammers build of those letters: aba and bab. For n = 5 we need three different letters. For example abcab is a three-letter sequence without stammers. In the sequence babab we have two stammers: ba and ab.


Write a program which:


In the first line of the standard input there is one positive integer n, 1 <= n <= 10000000.


Your program should write to the standard output. In the first line there should be one positive integer k equal to the minimal number of different letters that must appear in an n-element sequence having no stammers.

In the second line one should write the computed sequence without stammers as a word that comprises n lower case letters of English alphabet and is built only of the letters from a up to the k-th letter of the alphabet. If there are many such sequences, your program should write one of them.

You may assume 26 letters are enough.


For the following input data:
a correct answer is in the following output: